Matthew Saltzman wrote:
It will definitely print *something*. The question is, can you
guarantee what it will print.
In C89, no in C99, yes.
It's not addressed directly in the FAQ, but I believe it's possible to
prove that (unsigned) -2 must be the two's complement representation of
-2 in however many bits make up an int. I know there was some
controversy about that when the standard was being developed. In any
case, I don't know of any modern machine that doesn't represent negative
integers in two's complement.
Reach into your pocket, and pull out your calculator.
sizeof(char) == 1 is guaranteed by the standard. There's no reference
to "bytes", but it is commonly accepted that the char type is a byte.
Erm, from the Standard:
addressable unit of data storage large enough to hold any
member of the basic character set of the execution
It's possible to have chars that are not eight bits, but I can't think
of a modern machine that does that. There were some old machines
(Honeywells?) that had six-bit bytes and 36-bit words.
All this is based on my recollection of discussions in comp.lang.c and
comp.std.c when the standard was under development.
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