Andy Green wrote:
Michael Hennebry wrote:
printf("%d\n",-2);
does not result in
-2
It should.
printf, declared or not, will look for an int and get it.
printf("%u\n", -2);
is more interesting.
That will do exactly the same on big and little-endian machines too, if
the int size is the same.
Yes, of course. I gave a bad example. But, if one uses different sized
print formats from those in the int, it can do what I wrote...
printf("%d\n",(long int)-2);
can print
-1
for example, on a big-endian machine.
Mike
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