Am Sonntag, den 02.04.2006, 16:13 +0200 schrieb antonio montagnani: > I have a server with eth0 (192.168.0.1) and eth1(192.168.254.1) and I > connect by an Ethernet modem (192.168.254.254) by PPoE by eth1. > > I get these information from ifconfig and route -n > sbin/ifconfig > eth0 Link encap:Ethernet HWaddr 00:11:D8:BF:9F:05 > inet addr:192.168.0.1 Bcast:192.168.0.255 Mask:255.255.255.0 > inet6 addr: fe80::211:d8ff:febf:9f05/64 Scope:Link > UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 > RX packets:0 errors:0 dropped:0 overruns:0 frame:0 > TX packets:72 errors:0 dropped:0 overruns:0 carrier:0 > collisions:0 txqueuelen:1000 > RX bytes:0 (0.0 b) TX bytes:9676 (9.4 KiB) > Interrupt:21 > > eth1 Link encap:Ethernet HWaddr 52:54:05:E5:82:46 > inet addr:192.168.254.1 Bcast:192.168.254.255 Mask:255.255.255.0 > inet6 addr: fe80::5054:5ff:fee5:8246/64 Scope:Link > UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 > RX packets:888 errors:0 dropped:0 overruns:0 frame:0 > TX packets:934 errors:0 dropped:0 overruns:0 carrier:0 > collisions:0 txqueuelen:1000 > RX bytes:429031 (418.9 KiB) TX bytes:129154 (126.1 KiB) > Interrupt:21 Base address:0xec00 > > lo Link encap:Local Loopback > inet addr:127.0.0.1 Mask:255.0.0.0 > inet6 addr: ::1/128 Scope:Host > UP LOOPBACK RUNNING MTU:16436 Metric:1 > RX packets:3806 errors:0 dropped:0 overruns:0 frame:0 > TX packets:3806 errors:0 dropped:0 overruns:0 carrier:0 > collisions:0 txqueuelen:0 > RX bytes:6875583 (6.5 MiB) TX bytes:6875583 (6.5 MiB) > > ppp0 Link encap:Point-to-Point Protocol > inet addr:87.9.158.250 P-t-P:192.168.100.1 Mask:255.255.255.255 > UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1492 Metric:1 > RX packets:847 errors:0 dropped:0 overruns:0 frame:0 > TX packets:819 errors:0 dropped:0 overruns:0 carrier:0 > collisions:0 txqueuelen:3 > RX bytes:407494 (397.9 KiB) TX bytes:99093 (96.7 KiB) > /sbin/route -n > Kernel IP routing table > Destination Gateway Genmask Flags Metric Ref Use Iface > 192.168.100.1 0.0.0.0 255.255.255.255 UH 0 0 0 ppp0 > 192.168.0.0 0.0.0.0 255.255.255.0 U 0 0 0 eth0 > 192.168.254.0 0.0.0.0 255.255.255.0 U 0 0 0 eth1 > 169.254.0.0 0.0.0.0 255.255.0.0 U 0 0 0 eth1 > 0.0.0.0 192.168.100.1 0.0.0.0 UG 0 0 0 ppp0 > > > Is it correct?? Why a double entry for eth1?? > Tnx for help > -- > Antonio Montagnani > Skype : antoniomontag > 169.254.0.0 is the private range for ip-adresses windoze uses by default :-D Roger
