>> while on SPARC, it takes 6 instructions (of course, being RISC makes it
>> execute differently than x64)
>>
>> sethi %g1, $some_upper_bits
>> or %g1, $next_bitgroup
>> (shift-left)
>> or %g1, $next_bitgroup
>> (shift-left)
>> or %g1, $last_bitgroup
>>
>> BTW, T1 is cool, but that the 1U version only has space for 1 disk is
>> pretty limiting :/
>
> I have to believe that you can load 64 bit constant data from memory and
> don't have to do all this dancing with immediate loads. Therefore this
> must be faster or they wouldn't do it this way. Or is this a point that
> some unoptimized compiler could generate this code?
gcc 4.1.0 -m64. (Debian unstable)
I also tried
gcc version 4.0.0 20041019 (Red Hat 4.0.0-0.8sparc) <Aurora SPARC> -m64
generating (`objdump -DS test.o`)
0000000000000000 <main>:
#include <stdio.h>
int main(void) {
0: 9d e3 bf 40 save %sp, -192, %sp
return printf("%lld\n", 0x12345678abcdefULL);
4: 03 00 00 00 sethi %hi(0), %g1
8: 90 10 60 00 mov %g1, %o0 ! 0 <main>
c: 03 00 04 8d sethi %hi(0x123400), %g1
10: 82 10 60 56 or %g1, 0x56, %g1 ! 123456 <main+0x123456>
14: 85 28 70 20 sllx %g1, 0x20, %g2
18: 03 1e 2a f3 sethi %hi(0x78abcc00), %g1
1c: 82 10 61 ef or %g1, 0x1ef, %g1 ! 78abcdef <main+0x78abcdef>
20: 92 00 80 01 add %g2, %g1, %o1
24: 40 00 00 00 call 24 <main+0x24>
Jan Engelhardt
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