Hi Hugh, Pete,
> > This is wrong, Hugh. What do you think the priority of the second printk?
> > It's not log_lvl, that's for sure.
>
> Are you sure? I've not delved into the printk code itself, but this
> does follow the same pattern as in show_stack_log_lvl itself e.g. its
> "Call Trace:\n" line. (I am assuming print_context_stack ends with a
> newline, as it does.)
The code was correct (and was applied already as far as I can see.)
However, given that printk calls aren't exactly cheap, don't we want to
merge them where possible?
Merge a few printk calls in i386 traps.
Signed-off-by: Jean Delvare <[email protected]>
---
arch/i386/kernel/traps.c | 12 ++++--------
1 file changed, 4 insertions(+), 8 deletions(-)
--- linux-2.6.16-rc2.orig/arch/i386/kernel/traps.c 2006-02-06 07:50:57.000000000 +0100
+++ linux-2.6.16-rc2/arch/i386/kernel/traps.c 2006-02-06 19:42:10.000000000 +0100
@@ -114,8 +114,7 @@
static void print_addr_and_symbol(unsigned long addr, char *log_lvl)
{
- printk(log_lvl);
- printk(" [<%08lx>] ", addr);
+ printk("%s [<%08lx>] ", log_lvl, addr);
print_symbol("%s", addr);
printk("\n");
}
@@ -166,8 +165,7 @@
stack = (unsigned long*)context->previous_esp;
if (!stack)
break;
- printk(log_lvl);
- printk(" =======================\n");
+ printk("%s =======================\n", log_lvl);
}
}
@@ -196,14 +194,12 @@
break;
if (i && ((i % 8) == 0)) {
printk("\n");
- printk(log_lvl);
- printk(" ");
+ printk("%s ", log_lvl);
}
printk("%08lx ", *stack++);
}
printk("\n");
- printk(log_lvl);
- printk("Call Trace:\n");
+ printk("%sCall Trace:\n", log_lvl);
show_trace_log_lvl(task, esp, log_lvl);
}
More merges are possible, but I'm not sure how far we want to go.
Thanks,
--
Jean Delvare
-
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