Davide Libenzi <[email protected]> wrote:
>
> The attached patch uses the kernel min() macro, that is optimized has
> single compare by gcc-O2. Andrew, this goes over (hopefully ;) the bits
> you already have in -mm.
OK, well I've rather lost the plot with all the patches flying around.
I now have one single patch against epoll.c, below. Please confirm that
this is what was intended. If not, I'll drop it and let's start again.
From: Davide Libenzi <[email protected]>
The sys_epoll_wait() function was not handling correctly negative timeouts
(besides -1), and like sys_poll(), was comparing millisec to secs in
testing the upper timeout limit.
Signed-off-by: Davide Libenzi <[email protected]>
Signed-off-by: Andrew Morton <[email protected]>
---
fs/eventpoll.c | 8 ++++++--
1 files changed, 6 insertions(+), 2 deletions(-)
diff -puN fs/eventpoll.c~sys_epoll_wait-fix-handling-of-negative-timeouts fs/eventpoll.c
--- devel/fs/eventpoll.c~sys_epoll_wait-fix-handling-of-negative-timeouts 2005-09-24 23:01:00.000000000 -0700
+++ devel-akpm/fs/eventpoll.c 2005-09-24 23:02:50.000000000 -0700
@@ -101,6 +101,10 @@
/* Maximum number of poll wake up nests we are allowing */
#define EP_MAX_POLLWAKE_NESTS 4
+/* Maximum msec timeout value storeable in a long int */
+#define EP_MAX_MSTIMEO min(1000ULL * MAX_SCHEDULE_TIMEOUT / HZ, LONG_MAX / HZ - 1000ULL)
+
+
struct epoll_filefd {
struct file *file;
int fd;
@@ -1506,8 +1510,8 @@ static int ep_poll(struct eventpoll *ep,
* and the overflow condition. The passed timeout is in milliseconds,
* that why (t * HZ) / 1000.
*/
- jtimeout = timeout == -1 || timeout > (MAX_SCHEDULE_TIMEOUT - 1000) / HZ ?
- MAX_SCHEDULE_TIMEOUT: (timeout * HZ + 999) / 1000;
+ jtimeout = (timeout < 0 || timeout >= EP_MAX_MSTIMEO) ?
+ MAX_SCHEDULE_TIMEOUT : (timeout * HZ + 999) / 1000;
retry:
write_lock_irqsave(&ep->lock, flags);
_
-
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