On Sat, Jul 21, 2007 at 12:29:18PM +0200, Neil Thompson wrote:
> On Sat, Jul 21, 2007 at 11:06:20AM +0100, Andy Green wrote:
> > Somebody in the thread at some point said:
> > > On Sat, Jul 21, 2007 at 10:29:07AM +0100, Andy Green wrote:
> > >> Somebody in the thread at some point said:
> > >>> Installing: kernel ####################### [25/71]
> > >>> grubby fatal error: unable to find a suitable template
> > >>
> > >> export KERNVER=2.6.1234 ; grubby --config-file /tmp/grub.conf
> > >> --add-kernel /boot/vmlinuz-$KERNVER --initrd=/boot/initrd-$KERNVER.img
> > >> --title $KERNVER --set-default=/boot/vmlinuz-$KERNVER --copy-default
> > >>
> > >> This works as expected here and makes a fake entry at the top of
> > >> /tmp/grub.conf. Does it create the template error for you?
> > >>
> > >
> > > Yep - same error.
> > >
> > > grub.conf looks like this -
> >
> > then I get your error. The difference is that /boot/vmlinuz-2.6.22-rc7
> > exists and the ..rc7x file doesn't.
> >
> > straceing grubby with the ..rc7x bogus edit shows...
> >
> >
> > access("/boot/vmlinuz-2.6.22-rc7x", R_OK) = -1 ENOENT (No such file or
> > directory)
> > access("/boot/vmlinuz-2.6.22-rc7x", R_OK) = -1 ENOENT (No such file or
> > directory)
> > write(2, "grubby fatal error: unable to fi"..., 55grubby fatal error:
> > unable to find a suitable template
> > ) = 55
> >
> > Therefore... does /boot/vmlinuz-2.6.21-1.3194.fc7 exist on your box?
> >
>
> It does...BUT, when I do an strace, I get -
>
> access("/vmlinuz-2.6.21-1.3194.fc7", R_OK) = -1 ENOENT (No such file or directory)
> access("/vmlinuz-2.6.21-1.3194.fc7", R_OK) = -1 ENOENT (No such file or directory)
>
> without the "/boot" in front - this is curious and probably has something to do with
> the anaconda stuffup when I upgraded and my /boot partition disappeared. I've not been
> able to figure that one out yet.
>
And that's nailled it! I put the /boot in from of the filenames and it works. grubby seems
to expect there to be a /boot partition and for the files to be relative to that.
Now I have to try to get my /boot partition working again.
--
Cheers! (Relax...have a homebrew)
Neil
THEOREM: VI is perfect.
PROOF: VI in roman numerals is 6. The natural numbers < 6 which divide 6 are
1, 2, and 3. 1+2+3 = 6. So 6 is a perfect number. Therefore, VI is perfect.
QED
-- Arthur Tateishi
