On Sat, Jul 21, 2007 at 10:29:07AM +0100, Andy Green wrote:
> Somebody in the thread at some point said:
> >
> > Installing: kernel ####################### [25/71]
> > grubby fatal error: unable to find a suitable template
>
> What is in your /boot/grub/grub.conf at the moment?
>
> You might also try copying that file to, eg, /tmp/grub.conf and running
> grubby by hand with a test like
>
> export KERNVER=2.6.1234 ; grubby --config-file /tmp/grub.conf
> --add-kernel /boot/vmlinuz-$KERNVER --initrd=/boot/initrd-$KERNVER.img
> --title $KERNVER --set-default=/boot/vmlinuz-$KERNVER --copy-default
>
> This works as expected here and makes a fake entry at the top of
> /tmp/grub.conf. Does it create the template error for you?
>
Yep - same error.
grub.conf looks like this -
# grub.conf generated by anaconda
#
# Note that you do not have to rerun grub after making changes to this file
# NOTICE: You have a /boot partition. This means that
# all kernel and initrd paths are relative to /boot/, eg.
# root (hd2,0)
# kernel /vmlinuz-version ro root=/dev/VolGroup00/NLogVol02
# initrd /initrd-version.img
#boot=/dev/sda
default=0
timeout=5
splashimage=(hd2,0)/grub/splash.xpm.gz
hiddenmenu
title Fedora-base (2.6.21-1.3194.fc7)
root (hd2,0)
kernel /vmlinuz-2.6.21-1.3194.fc7 ro root=/dev/VolGroup00/NLogVol02 rhgb quiet
initrd /initrd-2.6.21-1.3194.fc7.img
--
Cheers! (Relax...have a homebrew)
Neil
THEOREM: VI is perfect.
PROOF: VI in roman numerals is 6. The natural numbers < 6 which divide 6 are
1, 2, and 3. 1+2+3 = 6. So 6 is a perfect number. Therefore, VI is perfect.
QED
-- Arthur Tateishi
