On 4/23/07, Dario Lesca <d.lesca@xxxxxxxxxx> wrote:
Hi, how to found into string 2 or more word, only if are all present? % echo "aa bb cc dd"|egrep -q '(bb|dd)' && echo found This command show "found" if bb OR dd are in string. But if I want show "found" only if bb AND dd are present into string. What egrep (or sed) command I must use? Many thanks for your reply! -- Dario Lesca <d.lesca@xxxxxxxxxx> -- fedora-list mailing list fedora-list@xxxxxxxxxx To unsubscribe: https://www.redhat.com/mailman/listinfo/fedora-list
Will this do? echo "aa bb cc dd" | grep bb | grep -q dd && echo found Not as clean because you are calling two greps instead of one. But it do what you seem to want to do. You can't use the -q on the first grep pipe because you need that output to feed into the second grep pipe. I don't know perl well at all so can't give input on that solution other than when I tested it with only one matching expression (i.e. echo "aa bb cc ed"), it still came back as found. I have a perl book and had a quick look to see if I could figure it out but no such luck. Jacques B.
