On Wed, 06 Dec 2006 21:36:54 -0500, Matthew Miller wrote: > On Thu, Dec 07, 2006 at 02:31:56AM +0000, Amadeus W. M. wrote: >> I'd normally ask this in comp.os.linux.misc, but my news server is not >> responding, so I'm asking it here. >> I have a bunch of files in a directory tree in which I want to replace a >> string A with string B. I'm trying to do this with xargs like so: >> grep -ri -l A . | xargs sed -e 's/A/B/g' >> and this does what I want, except, of course, that it outputs everything >> to stdout. Is there any way to pass the name of each input file as >> output for sed? > > You want the "sed -i" option, which edits files in place. (I believe this is > a GNU extension.) > > > -- > Matthew Miller mattdm@xxxxxxxxxx <http://mattdm.org/> > Boston University Linux ------> <http://linux.bu.edu/> > Worked beautifully, thanks!
