On Thu, Dec 07, 2006 at 02:31:56AM +0000, Amadeus W. M. wrote: > I'd normally ask this in comp.os.linux.misc, but my news server is not > responding, so I'm asking it here. > I have a bunch of files in a directory tree in which I want to replace a > string A with string B. I'm trying to do this with xargs like so: > grep -ri -l A . | xargs sed -e 's/A/B/g' > and this does what I want, except, of course, that it outputs everything > to stdout. Is there any way to pass the name of each input file as > output for sed? You want the "sed -i" option, which edits files in place. (I believe this is a GNU extension.) -- Matthew Miller mattdm@xxxxxxxxxx <http://mattdm.org/> Boston University Linux ------> <http://linux.bu.edu/>
