On Thu, 2006-10-12 at 18:44 +0100, Rob Andrews wrote: > On 12-Oct-2006 17:52.11 (BST), Dave Ihnat wrote: > > Anyway, the addresses you gave, converted to binary, are: > > > > 219.128.0.0 : 11011011.10000000.00000000.00000000 > > 219.137.255.255: 11011011.10001001.11111111.11111111 > > ^ > > The last bit that is invariant between the two is marked with the caret; > > converting back to a decimal dotted-quad (you can use 'dc' again--to set > > the input to binary, simply change the 'o' operand in the above example > > to an 'i', then input the binary value and print.) > > > > Mask > > 255.240.0.0 : 11111111.11110000.00000000.00000000 > > > > or, in conventional notation, 219.128.0.0/12. > > That's 219.138.0.0 - 219.143.255.255 though :) > Yep, as someone else already said, it cannot be done with a single netmask. The desired range encompasses 2 subnets. or you have overlap with other ranges as noted above. > -- > rob andrews :: pgp 0x01e00563 :: rob@xxxxxxxxxxxxx >
