On 10/12/06, Bill Rugolsky Jr. <brugolsky@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
On Wed, Oct 11, 2006 at 10:41:01AM -0400, Bill Rugolsky Jr. wrote:
> On Wed, Oct 11, 2006 at 09:30:13AM +0100, Dan Track wrote:
> > Hi
> >
> > Does anybody know where bc stores its calucation while calculating a
> > number. Basically I'm running 36000000^36000000.
>
> Rewriting it as (36^36000000) * (10 ^ 216000000)
> will save calculating, storing, and printing the 216M zeros,
> and will cut the first factor down to a "mere" 56M digits.
Just for kicks, I did this on a 4GB dual Opteron 246 running x86_64 Rawhide.
It took about 9 hours, and used about 200MB of VM (sorry, lost the output
of "time"), but the end result is:
(10656 ... <56026881 digits> ... 09376) * (10 ^ 216000000)
I wonder how the various other packages supporting multiple precision
(e.g., Pari) stack up.
Regards,
Bill Rugolsky
Wow. Great thanks for that. The last part of your number does it mean
there are 216000000 zeros in the final figure, or is it 216000001
zeros?
Thanks
Dan
