On Wed, Oct 11, 2006 at 09:30:13AM +0100, Dan Track wrote: > Hi > > Does anybody know where bc stores its calucation while calculating a > number. Basically I'm running 36000000^36000000. Rewriting it as (36^36000000) * (10 ^ 216000000) will save calculating, storing, and printing the 216M zeros, and will cut the first factor down to a "mere" 56M digits. If you want the result in a non-decimal base, you'll have to factor the product differently. Regards, Bill Rugolsky
