System is AMD-Athlon
64 based. hda is 120GB and contains Windows XP on partition hda1. hdb is 60GB
and contain 64-bit version of Fedora Core 3. /boot is on hdb1 (ext3) followed by
a Logical Volume containing / (reiserfs) and the swap partition. This was the
default partitioning performed by Fedora. Grub was installed to the
MBR.
Now, when I boot, I
get error 17 in Grub stage 1.5. From the Grub manual this is
:
I have a floppy
which boots to a Grub shell. Now if I type in the following I can boot Fedora
Core 3:
root
(hd1,0)
kernel
/vmlinuz-2.6.9-1.667 ro root=/dev/VolGroup00/LogVol00 rhgb
quiet
initrd
/initrd-2.6.9-1.667.img
boot
and away Fedora
goes. No problem.
Also, I can boot
Windows XP from the Grub shell by the following:
rootnoverify
(hd0,0)
makeactive
chainloader
+1
boot
A few seconds later,
I have Windows XP up and running.
The contents of my
grub.conf are as follows:
# grub.conf
generated by anaconda
#
# Note that you do
not have to rerun grub after making chnages to this file
# NOTICE: You
have a /boot partition. This means that you
#
all kernel and initrd paths are relative to /boot/, eg.
#
root (hd1,0)
# kernel /vmlinuz-version
ro root=/dev/VolGroup00/LogVol00
#
initrd
/initrd-version.img
#boot=/dev/hda
default=0
timeout=5
splashimage=(hd1,0)/grub/splash.xpm.gz
hiddenmenu
title Fedora Core
(2.6.9-1.667)
root
(hd1,0)
kernel
/vmlinuz-2.6.9-1.667 ro root=/dev/VolGroup00/LogVol00 rhgb
quiet
initrd
/initrd-2.6.9-1.667.img
title Windows XP
Professional SP2
rootnoverify (hd0,0)
chainloader +1
As far as I can see,
these commands are the same as I typed into the Grub shell, with the exception
that
I also put a
'makeactive' command in when booting Windows from the Grub shell. However, this
does not make any
difference, so
what is
going on?
I have read that /boot
should be on the first hard disk. Is this correct? Why then can I boot from the
floppy?
I have also read that
people have had problems with 64-bit.
Hopefully some of you
clever people can help here.
Thanks
Steve
Black
