Pardon the question. After searching for the reason why mysqld gives this error: "Timeout error occurred trying to start MySQL Daemon." only after the mysql root password is specified I found this bug on bugzilla #108779. Bug status is closed with the resolution reading RAWHIDE. That doesn't tell me much. Ok I know the bug was fixed...and I know it's in RAWHIDE but why hasn't this been fixed in an update for Fedora and released so that yum update will correct the problem? In the meantime I tried some of the examples listed in that bug report and they did not work. What I did find that works is this: Change: if [ -n "`/usr/bin/mysqladmin ping 2> /dev/null`" ]; then to: if [ -n "`/usr/bin/mysqladmin ping -u 2> /dev/null`" ]; then on lines 42 and 48 (I think it was lines 42 and 48). I found that if I type: mysql -u root -p and once logged in with my password type: SELECT user, host, password FROM mysql.user; I see that there is a user with no name and no password already there besides the root user. mysql> SELECT user, host, password FROM mysql.user; +------+-----------------+------------------+ | user | host | password | +------+-----------------+------------------+ | root | localhost | 91d5dek93805l97f | | root | dev.local.lan | 91d5dek93805l97f | | | localhost | | | | dev.local.lan | | +------+-----------------+------------------+ 4 rows in set (0.00 sec) That is why I can use the "-u" in the modifications above without specifying a mysql username (I think). So did anyone else experience this? And is my workaround a good idea or not? Thanks, Scott
