On Fri, 12 Oct 2007, Yasunori Goto wrote:
> If pages on the new node available, slub can use it before making
> new kmem_cache_nodes. So, this callback should be called
> BEFORE pages on the node are available.
If its called before pages on the node are available then it must
fallback and cannot use the pages.
> +#if defined(CONFIG_NUMA) && defined(CONFIG_MEMORY_HOTPLUG)
> +static int slab_mem_going_offline_callback(void *arg)
> +{
> + struct kmem_cache *s;
> + struct memory_notify *marg = arg;
> + int local_node, offline_node = marg->status_change_nid;
> +
> + if (offline_node < 0)
> + /* node has memory yet. nothing to do. */
Please clarify the comment. This seems to indicate that we should not
do anything because the node still has memory?
Doesnt the node always have memory before offlining?
> + return 0;
> +
> + down_read(&slub_lock);
> + list_for_each_entry(s, &slab_caches, list) {
> + local_node = page_to_nid(virt_to_page(s));
> + if (local_node == offline_node)
> + /* This slub is on the offline node. */
> + return -EBUSY;
> + }
> + up_read(&slub_lock);
So this checks if the any kmem_cache structure is on the offlined node? If
so then we cannot offline the node?
> + kmem_cache_shrink_node(s, offline_node);
kmem_cache_shrink(s) would be okay here I would think. The function is
reasonably fast. Offlining is a rare event.
> +static void slab_mem_offline_callback(void *arg)
We call this after we have established that no kmem_cache structures are
on this and after we have shrunk the slabs. Is there any guarantee that
no slab operations have occurrent since then?
> +{
> + struct kmem_cache_node *n;
> + struct kmem_cache *s;
> + struct memory_notify *marg = arg;
> + int offline_node;
> +
> + offline_node = marg->status_change_nid;
> +
> + if (offline_node < 0)
> + /* node has memory yet. nothing to do. */
> + return;
Does this mean that the node still has memory?
> + down_read(&slub_lock);
> + list_for_each_entry(s, &slab_caches, list) {
> + n = get_node(s, offline_node);
> + if (n) {
> + /*
> + * if n->nr_slabs > 0, offline_pages() must be fail,
> + * because the node is used by slub yet.
> + */
It may be clearer to say:
"If nr_slabs > 0 then slabs still exist on the node that is going down.
We were unable to free them so we must fail."
> +static int slab_mem_going_online_callback(void *arg)
> +{
> + struct kmem_cache_node *n;
> + struct kmem_cache *s;
> + struct memory_notify *marg = arg;
> + int nid = marg->status_change_nid;
> +
> + /* If the node already has memory, then nothing is necessary. */
> + if (nid < 0)
> + return 0;
The node must have memory???? Or we have already brought up the code?
> + /*
> + * New memory will be onlined on the node which has no memory so far.
> + * New kmem_cache_node is necssary for it.
"We are bringing a node online. No memory is available yet. We must
allocate a kmem_cache_node structure in order to bring the node online." ?
> + */
> + down_read(&slub_lock);
> + list_for_each_entry(s, &slab_caches, list) {
> + /*
> + * XXX: The new node's memory can't be allocated yet,
> + * kmem_cache_node will be allocated other node.
> + */
"kmem_cache_alloc node will fallback to other nodes since memory is
not yet available from the node that is brought up.¨ ?
> + n = kmem_cache_alloc(kmalloc_caches, GFP_KERNEL);
> + if (!n)
> + return -ENOMEM;
> + init_kmem_cache_node(n);
> + s->node[nid] = n;
> + }
> + up_read(&slub_lock);
> +
> + return 0;
> +}
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