> > Original code completely pads the destination with zeroes,
> > while yours only adds the last zero. Your code does what
> > strncpy() is said to do, but maybe there's a particular
> > reason for it to behave differently in the kernel
> No, the kernel's strncpy() behaves the same as the one in libc. Run
> "man strncpy" if you don't believe me.
> In the common case where you just want to copy a string and avoid
> overflow use strlcpy() instead
Oops you're right! Maybe someone should take a look if the strncpy's
should be replaced by strlcpy's then because it is (ought to be) faster.
Folkert van Heusden
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