On Sep 18, 2006, at 08:34:25, Jan Engelhardt wrote:
Sure, people said that too when going from 16 bits to 32 bits,
but that was only a factor 2^16 difference. This time it's the
square of the previous difference.
Not quite the square :)
2^32 is the square of 2^16 :)
As mentioned above, "the square of the previos" [16 to 32]
"difference". Call me nitpicky, but:
(2^32 - 2^16)^2 != (2^64 - 2^32)
Well into the nitpicking territory... I think you missed where he
said "factor 2^16 difference". So these:
Going from 32 to 64: (2^64 - 2^32)
Going from 16 to 32: (2^32 - 2^16)
Should actually be these:
Going from 32 to 64: (2^64 / 2^32)
Going from 16 to 32: (2^32 / 2^16)
And:
(2^32 / 2^16)^2 = (2^64 / 2^32) => (2^16)^2 = (2^32)
Cheers,
Kyle Moffett
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