>> > Sure, people said that too when going from 16 bits to 32 bits,
>> > but that was only a factor 2^16 difference. This time it's the
>> > square of the previous difference.
>>
>> Not quite the square :)
>
> 2^32 is the square of 2^16 :)
Going from 32 to 64: (2^64 - 2^32)
Going from 16 to 32: (2^32 - 2^16)
As mentioned above, "the square of the previos" [16 to 32] "difference".
Call me nitpicky, but:
(2^32 - 2^16)^2 != (2^64 - 2^32)
>--
> What is important? What you want to be true, or what is true?
Jan Engelhardt
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