Re: [PATCH 2/6] i386 virtualization - Remove some dead debugging code

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Chris Wright wrote:

* [email protected] ([email protected]) wrote:
This code is quite dead.  Release_thread is always guaranteed that the mm has
already been released, thus dead_task->mm will always be NULL.

Signed-off-by: Zachary Amsden <[email protected]>
Index: linux-2.6.13/arch/i386/kernel/process.c
===================================================================
--- linux-2.6.13.orig/arch/i386/kernel/process.c	2005-08-15 10:46:18.000000000 -0700
+++ linux-2.6.13/arch/i386/kernel/process.c	2005-08-15 10:48:51.000000000 -0700
@@ -421,17 +421,7 @@

void release_thread(struct task_struct *dead_task)
{
-	if (dead_task->mm) {
-		// temporary debugging check
-		if (dead_task->mm->context.size) {
-			printk("WARNING: dead process %8s still has LDT? <%p/%d>\n",
-					dead_task->comm,
-					dead_task->mm->context.ldt,
-					dead_task->mm->context.size);
-			BUG();
-		}
-	}
-
+	BUG_ON(dead_task->mm);

This BUG_ON() has different semantics than old dead one.  Is there a
point?  exit_mm() has already reset this to NULL, no?

Yes, completely. This BUG() could be eliminated entirely, as trivial inspection shows. I can't fathom a single reason why it should still exist, but the presence of it in the first place made be wonder if there may be some erudite reason for it. Thus I raised the BUG to a higher power - obviously the LDT is gone if the MM is gone.

Zach
-
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