On Sun, 5 Jun 2005, Thomas Gleixner wrote:
> On Sun, 2005-06-05 at 09:58 +0200, Esben Nielsen wrote:
> > On Sun, 5 Jun 2005, Thomas Gleixner wrote:
> >
> > > [...]
> > > *
> > > * Based on simple lists (include/linux/list.h).
> > > @@ -17,35 +22,50 @@
> > > * a priority too (the highest of all the nodes), stored in the head
> > > * of the list (that is a node itself).
> > > *
> > > - * Addition is O(1), removal is O(1), change of priority of a node is
> > > - * O(1).
> > > + * Addition is O(N), removal is O(1), change of priority of a node is
> > > + * O(N).
> > > *
> > > - * Addition and change of priority's order is really O(K), where K is
> > > - * a constant being the maximum number of different priorities you
> > > - * will store in the list. Being a constant, it means it is O(1).
> > > - *
> >
> > What is N? The number of nodes in the list or the number of different
> > priorities? If it is the number of nodes in total this exercise is
> > worthless: You could just as well have a sorted list.
> >
> > But I hope and also think that the original explanation was correct.
>
> Sorry, I meant K the number of different priorities.
>
> I just find it completely bogus, that O(K) == O(1) for any K != 1.
>
> tglx
>
When K is a constant or bounded by a constant (140 in this application)
any function which is O(K) is O(1) per definition of O!
Esben
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