I want to know when i use
trap 'rm -f /tmp/my_tmp_file_$$' INT
why shell itself capture the single and she shellscript exit.
Here is the code from << Beginning Programming>>
#!/bin/sh
trap 'rm -f /tmp/my_tmp_file_$$' INT
echo creating file /tmp/my_tmp_file_$$
date > /tmp/my_tmp_file_$$
echo "Press interrupt (Ctrl-C) to interrupt...."
while [ -f /tmp/my_tmp_file_$$ ]; do
echo File exists
sleep 1
done
echo The file no longer exists
trap INT
echo creating file /tmp/my_tmp_file_$$
date > /tmp/my_tmp_file_$$
echo "Press interrupt (Ctrl-C) to interrupt...."
while [ -f /tmp/my_tmp_file_$$ ]; do
echo File exists
sleep 1
done
echo We never get here
exit 0
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