On Thu, 2010-12-30 at 10:34 -0800, S Mathias wrote:
> I just can't google for it:
>
> I'm searching for a "bash" "one liner" (awk, perl, or anything) for this:
>
Attached is a python program that counts the number of words in a file.
This could easily be slightly altered and combined with find to do what
you want.
--
=======================================================================
"Plaese porrf raed." -- Prof. Michael O'Longhlin, S.U.N.Y. Purchase
=======================================================================
Aaron Konstam telephone: (210) 656-0355 e-mail: akonstam@xxxxxxxxxxxxx
#!/usr/bin/env python
import string
def WordsOccur():
fileName = raw_input("Enter the name of the file: ")
f=open(fileName,"r")
wordList=string.split(f.read())
f.close()
occursDict={}
for word in wordList:
occursDict[word] = occursDict.get(word, 0) +1
print "File %s has %d words (%d are unique)" \
% (fileName, len(wordList), len(occursDict) )
print occursDict
if __name__ == '__main__':
WordsOccur()
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