On 14Jul2010 21:33, Sjoerd Mullender <sjoerd@xxxxxxx> wrote: | On 2010-07-14 21:19, Michael Hennebry wrote: | > On Wed, 14 Jul 2010, Sjoerd Mullender wrote: | >> On 2010-07-14 19:26, Mike Wright wrote: | >>> Will somebody tell me the symbol to use for a linefeed in substitutions | >>> as in | >>> :s1,$#</tag>#</tag>linefeed#g | >> | >> Type control-V control-M. | > | > That would be carriage return. | > convrol-V control-J might work. | > You might not be able to substitute a linefeed with vi. | > I think sed can do it. | | I know it's a carriage return. Did you try it? If not, do. Linefeed | (control-J) doesn't work. He hasn't tried it, or he'd know it is The Way. Mike, vi turns a literal carriage return in a substitution into a linefeed for you. I use this all the time; Sjoerd's suggestion is exactly what you want. BTW, you know you can use "%" for 1,$ ? And "&" for the text matched by the whole pattern? The former is just convenient, but the "&" thing is very handy with big (or varying) patterns. :%s#</tag>#&^V^M#g Cheers, -- Cameron Simpson <cs@xxxxxxxxxx> DoD#743 http://www.cskk.ezoshosting.com/cs/ Nope. First, you need to learn how to use vi, the editor from hell (vi vi vi -- the number of the beast), ... - Dan Sorenson, DoD#1066, <z1dan@xxxxxxxxxxxxxxxxx> -- users mailing list users@xxxxxxxxxxxxxxxxxxxxxxx To unsubscribe or change subscription options: https://admin.fedoraproject.org/mailman/listinfo/users Guidelines: http://fedoraproject.org/wiki/Mailing_list_guidelines
