On Sat, Jun 19, 2010 at 7:05 PM, Patrick O'Callaghan
<pocallaghan@xxxxxxxxx> wrote:
> A script I'm writing needs to work out the target of a symbolic link,
> i.e. given:
>
> $ touch foo
> $ ln -s foo bar
>
> the function should print bar when given foo as a parameter. The manual
> says "ls -L" should do this, but it doesn't seem to work:
>
> $ touch foo
> $ ln -s foo bar
> $ ls -l foo bar
> lrwxrwxrwx 1 poc poc 3 Jun 19 21:32 bar -> foo
> -rw-rw-r-- 1 poc poc 0 Jun 19 21:32 foo
> $ ls -L bar
> bar
>
> (should give foo)
>
> Have I misunderstood what "ls -L" does? Is there a bug? And is there a
> better way of doing this?
>
> poc
Compare and contrast....
$ touch foo
$ ln -s foo bar
$ ls -lL *
-rw-rw----. 1 mitch mitch 0 Jun 19 23:48 bar
-rw-rw----. 1 mitch mitch 0 Jun 19 23:48 foo
$ ls -l *
-rwxrwxrwx. 1 mitch mitch 3 Jun 19 23:49 bar -> foo
-rw-rw----. 1 mitch mitch 0 Jun 19 23:48 foo
--
NiftyFedora
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