Dan Thurman wrote: > Kevin Martin wrote: >> >> Gordon Messmer wrote: >> >>> Dan Thurman wrote: >>> >>>> I tested your suggestion above with and without -r option >>>> but could not make it work as an "AND operator": >>>> >>>> # echo "foo har" | sed -re '/foo/{/bar/{s/foo/goo/}}' >>>> goo har >>>> >>> $ rpm -q sed >>> sed-4.1.5-11.fc10.x86_64 >>> >>> $ echo "foo har" | sed -re '/foo/{/bar/{s/foo/goo/}}' >>> foo har >>> >>> >> >> $ echo "foo har" | sed -e "s/foo/goo/g" -e "s/har/bar/g" >> goo bar >> >> Is this what you're trying to do? >> >> Kevin >> > No. The result should be: (foo AND har) = (1&0)=0 > so the inside nested brackets should not be allowed to > run and the original string (foo har) is returned. > > Dan > Ah, I missed the first part of the conversation where it was explained what you were doing (ah, snipped mail). Sorry for butting in. Kevin -- fedora-list mailing list fedora-list@xxxxxxxxxx To unsubscribe: https://www.redhat.com/mailman/listinfo/fedora-list Guidelines: http://fedoraproject.org/wiki/Communicate/MailingListGuidelines