iptables count port 80

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I want to measure the amount of traffic (Linux) on port 80 (Tomcat)
separated by incoming and outgoing. I figure maybe I can do this
(after creating the chains):

iptables -A INPUT -d 10.0.0.50 -p tcp -m tcp --dport 80 -j COUNTIN
iptables -A INPUT -s 10.0.0.50 -p tcp -m tcp --sport 80 -j COUNTOUT
iptables -A COUNTIN -j ACCEPT
iptables -A COUNTOUT -j ACCEPT

and then do an iptables -L -nv tp count the bytes. This gives output
like this:

Chain INPUT (policy ACCEPT 510M packets, 26G bytes)
pkts bytes target prot opt in out source destination
365 29891 COUNTIN tcp -- * * 0.0.0.0/0 10.0.0.50
tcp dpt:80
0 0 COUNTOUT tcp -- * * 10.0.0.50 0.0.0.0/0
tcp spt:80
...
...
Chain COUNTIN (1 references)
pkts bytes target prot opt in out source destination
365 29891 ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0

Chain COUNTOUT (1 references)
pkts bytes target prot opt in out source destination
0 0 ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0



Now a couple questions.

1. Will this screw up normal TCP/UDP behavior? It does not seem to.

2. Do I need to do the "ACCEPT" lines? Will normal TCP and IP still
work? It seems like I need it for 2 reasons:
1 - So the packets actually get accepted. But maybe they will anyway?
2 - When I use -Z (like iptables -Z COUNTIN) to zero the chain, if I
don't have the -j ACCEPT those two chains won't be listed and I can't
zero the chains. I can zero INPUT but that will zero all INPUT.
(Now that I think of it, COUNTOUT should be on OUTPUT not INPUT but
the same question applies)

It is easier to grep "COUNTIN tcp" and get the first 2 fields than
grepping for "Chain COUNTIN", reading 2 lines and then getting
the fields (which I suppose could be done with awk).

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