Antonio Olivares wrote:
$ cat /etc/redhat-release
Fedora release 8 (Werewolf)
$ uname -o
GNU/Linux
John
--
Tried this command in slax
uname -o which according to man uname
-o, --operating-system
print the operating system
Slax is based on Slackware Linux, here's the result(s)
root@slax:~# cat /etc/slax-version
Slax 6.0.7
root@slax:~# cat /etc/slackware-version
Slackware 12.1.0
root@slax:~# uname -o
GNU/Linux
It is GNU/Linux. Should this be tried with Ubuntu, Suse, Gentoo, ..., etc?
Let's see:
rpm -qf `which uname`
coreutils-6.10-27.fc9.x86_64
and of course rpmq -i coreutils:
Name : coreutils Relocations: (not relocatable)
Version : 6.10 Vendor: Fedora Project
Release : 27.fc9 Build Date: Fri 04 Jul 2008 12:37:00 PM EDT
Install Date: Wed 09 Jul 2008 02:15:25 PM EDT Build Host: x86-5
Group : System Environment/Base Source RPM: coreutils-6.10-27.fc9.src.rpm
Size : 11290040 License: GPLv3+
Signature : DSA/SHA1, Tue 08 Jul 2008 11:23:50 AM EDT, Key ID b44269d04f2a6fd2
Packager : Fedora Project
URL : http://www.gnu.org/software/coreutils/
Summary : The GNU core utilities: a set of tools commonly used in shell scripts
Description :
These are the GNU core utilities. This package is the combination of
the old GNU fileutils, sh-utils, and textutils packages.
So, you want to use a GNU utility to "prove" that the OS is GNU/Linux?
Sounds rather like GNU made an assertion and is using that assertion as
a proof.
BTW, I wouldn't have expected a package of GNU utilities to say anything
else.
--
Kevin J. Cummings
kjchome@xxxxxxx
cummings@xxxxxxxxxxxxxxxxxx
cummings@xxxxxxxxxxxxxxxxxxxxxxx
Registered Linux User #1232 (http://counter.li.org)
--
fedora-list mailing list
fedora-list@xxxxxxxxxx
To unsubscribe: https://www.redhat.com/mailman/listinfo/fedora-list
