Re: sort with tab field separator

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On Saturday 22 March 2008 21:38:46 Nicholas Robinson wrote:
> On Saturday 22 March 2008 21:18:11 Amadeus W.M. wrote:
> > You would think specifying tab as a field separator for sort would work
> > like this:
> >
> > cat file | sort -k 3 -t "\t"
> >
> > It doesn't:
> >
> > sort: multi-character tab `\\t'
> >
> >
> > So after a little search and some trial and error I got this to work:
> >
> > cat file | sort -k 3 -t "`/bin/echo -e '\t'`"
> >
> >
> > For my own curiosity, can someone please illuminate me as to why the
> > first incantation does not work as expected? Is there a more natural way
> > to specify \t other than echo?
>
> Take the double quotes out in your first attempt. So command becomes
>
> cat file | sort -k 3 -t \t
>
> Nick

Sorry, I was a little bit quick off the mark. The \t doesn't yield a tab 
character (see below) as you were implying and I went along with in the first 
example! If you take the double quotes out as I suggested, then the field 
separator becomes the character t!

I think (being a little more cautious this time!) that you want:

\ followed by Ctrl V followed by Ctrl I

If I remember correctly, sort interprets a tab as a default field separator 
anyway.

As to the why: it is because the -t takes an argument which is a character. 
Putting double quotes around it stops the \ being elided and so \t as two 
characters \ and t are presented to sort which is expecting only one 
character. Hence its moan. Try echo "\t" and you will see what I mean.

In my second attempt above, the Ctrl V stops the tab character (Ctrl I) being 
expanded on the command line and the \ joins the tab character to the t.

HTH

Nick


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