On 10/31/07, Jacques B. <jjrboucher@xxxxxxxxx> wrote: > On 10/31/07, Dario Lesca <d.lesca@xxxxxxxxxx> wrote: > > In this shell script: > > > > > #!/bin/bash > > > i=0 > > > > > > printf "a a a\nb b b\nc c c\n" | > > > while read x > > > do > > > i=$[i+1] > > > echo "$x: ($i)" > > > done > > > > > > echo $i > > > > with this output: > > > > > a a a: (1) > > > b b b: (2) > > > c c c: (3) > > > 0 > > > > How to I can get the value (3) for $i out of the while loop? > > > > Many thanks > > > > -- > > Dario Lesca <d.lesca@xxxxxxxxxx> > > Is there a reason for using while instead of for? > > for x in $(ls dir/) > do > ..... > done > > Jacques B. > The one caution when dealing with path/filenames is spaces. That was discussed not long ago and a few suggestions were given, mine being to change the $IFS variable but others were suggested that also worked if I recall. Jacques B.
