Am Dienstag, den 31.07.2007, 11:00 -0400 schrieb Miner, Jonathan W (CSC)
(US SSA):
> -----Original Message-----
> From: fedora-list-bounces@xxxxxxxxxx on behalf of Mark Haney
> Sent: Tue 07/31/2007 10:52 AM
> To: For users of Fedora
> Cc:
> Subject: Sort files by filename
>
> This is really a general linux question. I have a series of files in a
> format like this:
>
> XXXX20070515_112011_942_10.bz2
> XXXX20070515_112011_942_12.bz2 etc,
>
> and I am trying to find a way to do 2 things, one, sort these files in
> order, and then once in order, find the files that are numerically
> missing based on the last 2 numbers in the file name. So if I have (as
> above I want to know that file XXXX20070515_112011_942_11.bz2 is
> missing. Can someone get me started on this, I'm stumped.
Just an example tip which simply works with a counter, hope helps you.
a) Do you really need the sorting stuff? I didnt mess with that.
b) the counter:
[rodolfoap] /home/rodolfoap > for n in $(seq 10 40); do touch XXXX20070515_112011_942_${n}.bz2; done
[rodolfoap] /home/rodolfoap > rm XXXX20070515_112011_942_11.bz2
[rodolfoap] /home/rodolfoap > rm XXXX20070515_112011_942_22.bz2
[rodolfoap] /home/rodolfoap > rm XXXX20070515_112011_942_33.bz2
[rodolfoap] /home/rodolfoap > for n in $(seq 10 40); do if [ ! -e *_${n}.bz2 ]; then echo NOT FOUND: $n; fi; done
NOT FOUND: 11
NOT FOUND: 22
NOT FOUND: 33
[rodolfoap] /home/rodolfoap >
Good luck.
--
Rodolfo Alcazar
Responsable red y datos
Deutsche Gesellschaft für
Technische Zusammenarbeit (GTZ) GmbH
Programa de Apoyo a la Gestión Pública Descentralizada y
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Tel: +591 22417628 (121)
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Email: rodolfo.alcazar@xxxxxxxxxxxx
