"1962316k is actually occupied by my active"
How do you calculate that 1962316k is being occupied by your active processes?
On 2/27/07, Frank Cox <theatre@xxxxxxxxxxx> wrote:
On Tue, 27 Feb 2007 14:12:43 -0800 (PST)
Ravi Malghan <rmalghan@xxxxxxxxx> wrote:
> Hi: I have installed Fedora 6 on a laptop with 756MB
> RAM. With no application started when the machine
> boots up, the top is saying that, 601308K is being
> used.
Type this:
free
Look at the second line of output data.
For example, this is what I have on this machine right now:
$ free
total used free shared buffers cached
Mem: 2057836 1958356 99480 0 77972 1437864
-/+ buffers/cache: 442520 1615316
Swap: 2031608 344 2031264
I am using 442520k of memory, but 1962316k is actually occupied by my active
processes, plus what amounts to a cache of what I have been doing recently just
in case I might want to do it again soon.
Linux uses all available ram for that sort of a cache unless it is otherwise
required for something else whereupon it is immediately released and given to
the process that asked for it.
--
MELVILLE THEATRE ~ Melville Sask ~ http://www.melvilletheatre.com
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