edwardspl@xxxxxxxxxx wrote: >>> chmod g+rwx ( What number of g+rwx, eg : ?77 ) /home/edward >> >> You can use the symbolic form literally. I think it's easier to >> understand. Let the computer do the binary/octal math. >> g+rwx means add the read, write, and execute bits for the group. > > But I want to know what no of g+rwx... The + means it is added to the bits already permitted. Look at them as groups of 3 bits in binary and take the octal value. user group other rwx rwx rwx You'll start with a home dir having rwx --- --- so that's 111 000 000 binary or 700 octal. Add the group rwx and you get 111 111 000 or 770 octal >>> chmod +t ( What number of +t ) /home/edward That's one more bit to the left, 1 000 000 000 binary, so 1000 octal. Add that to what you have. >> Same here, you can type it that way and it means add the "sticky" bit. > > Also want to know... Altogether, the octal value for the mode ends up at 1770. But, as I said before the computer does a better job of thinking in octal. >>> chown root /home/edward/ All_dot_filenames >> >> Don't get carried away with wildcards on this one. .* will also match >> .. which is your parent directory. >> > ok, > chown root /home/edward/.* I meant not to do that. In this case it won't break anything because the parent (..) dir of /home/edward will alread be owned by root, but it is a bad idea in general to wildcard .* -- Les Mikesell lesmikesell@xxxxxxxxx
