>> >> I have downloaded and installed the 2.6.16-1.2122_FC5 kernal
update
>> >> but
>> >> unfornatunatly this does not solve the problem. The
eciadsl-doctor
>> >> program
>> >> still shows that the n_hdlc module is not found, it also
reports >> >> that
>> >> I
>> >> am
>> >> using the 2.6.15-1.2054_FC5 kernal, how can this be when I have
>> >> just
>> >> installed the updated kernal with no problems? Am I missing
>> >> something?
>> >
>> > You won't be using the 2.6.16-1.2122_FC5 kernel until you've >>
> rebooted.
>> >
>> > Paul,
>>
>> I have rebooted a couple of times plus the computer was off
overnight!
>
> What's the output of:
>
> $ rpm -qa kernel\*
kernel-2.6.15-1.2054_FC5
> $ uname -a
Linux linux 2.6.15-1.2054_FC5
> $ cat /etc/sysconfig/kernel
UPDATEDEFAULT=yes
DEFAULTKERNEL=kernel
> $ cat /etc/grub.conf
default=0
timeout=5
splashimage=(hdo,0)/grub/splash.xpm.gz
hiddenmenu
title fedora Core (2.6.15-1.2054_FC5)
root (hd0,0)
kernel /vmlinux-2.6.15-1.2054_FC5 ro root=/dev/VolGroup00/LogVol00
rhgb
quiet
initrd /initrd-2.6.15-1.2054_FC5.img
By the looks of it the kernel has not been updated, strange as it
installed
with no problems!
The only explanation I can think of for this is that you downloaded and
installed the SRPM (.src.rpm) instead of the binary RPM for your
system's architecture (e.g. .i386.rpm or .x86_64.rpm).
The kernel I downloaded was kernel-2.6.16-1.2122_FC5.i586.rpm, I tried
this one as I could not find an i386 one.
That's because there isn't one :-)
You may well have an i686 kernel currently:
$ rpm -qa --qf '%{NAME}-%{VERSION}-%{RELEASE}.%{ARCH}\n' kernel\*
The latest kernel update should always be available here:
http://download.fedora.redhat.com/pub/fedora/linux/core/updates/5/i386/
Get the one that's the same arch as your current kernel.
Ok, I have now managed to install the kernel update and rebooted. But I
still dont have the n_hdlc module which is required by the eciadsl driver!
I was told that the n_hdlc module was in the latest kernel update!, any
ideas as to how I can get the n_hdlc module?
Many thanks,
Garry.
