M E Fieu wrote: > Hi.. Need to ask you a simple script question, I used the date command to get the yesterday web > log file using the following command echo ex`date -d yesterday +%y%m%d.log` in Linux. I want to > create a simple script to cat /home/IT/ex060530.log > kr.log using the following script but it is > not working. May I know how do I put the output of echo ex`date -d yesterday +%y%m%d.log into cat > /home/IT/xxxx > kr.log ? > > [root@w2 krweblog3]# echo ex`date -d yesterday +%y%m%d.log` > ex060530.log > > [root@w2 krweblog3]# vi krweblog.sh > > #!/bin/sh > # > KRWEBLOG3= echo ex`date -d yesterday +%y%m%d.log` > cat /home/IT/$KRWEBLOG3 > kr.log > For thing like this, I like to use something like: KRWEBLOG=$(date -d yesterday +ex%y%m%d.log) cat /home/IT/$KRWEBLOG3 > kr.log KRWEBLOG will have the value of ex060530.log if I ran it now on my system. Enclosing a command inside $() returns the output of the command. You could also use: KRWEBLOG=`date -d yesterday +ex%y%m%d.log` but I find the $() format easyer to read. Mikkel -- Do not meddle in the affairs of dragons, for thou art crunchy and taste good with Ketchup!
