How to compare file size in script?

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Hi,

I want to write a script to compare file sizes.  My script is like this:

#!/bin/sh
ls -l /tmp/test/t1 | awk '{print $5}' > thesize
echo `cat thesize`
if [ `cat thesize` > 300000 ]
then
        echo "big file: thesize"
        exit 0
fi

But, no matter how small or big the file t1 is, it always display:

11190
big file: thesize

The actual size of t1 is 11190.  I also tried the other code:

#!/bin/sh
thissize=`ls -l /tmp/test/t1 | awk '{print $5}'`
echo "$thissize"
if [ $thissize > 300000 ]
then
        echo "big file: $thissize"
        exit 0
fi

then, it displays:

11190
big file: 11190

What's wrong in the codes?  How to fix it?

Thanks!

Hongwei Li


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