Hi,
'find' is your best friend in that case ...
Regards
Alex
On Tue, 2005-02-01 at 06:05 -0500, fly over wrote:
> Hi guys,
> i'm trying to write a script for following purpose.
>
> shell program will be used by Linux/Unix sysadmins to search for SUID/SGID files. The default directory to search is the present working directory, however, the user may include a directory name on the command line as an alternative. Also, if the user includes the argument '-R' then the search should include all subdirectories recursively. Also, the '-G' argument will include SGID files which by default are not shown. The output of the script should show the absolute pathname of the file and the owner.
>
>
> Please help me in performin such task.
>
> i'm trying using this line:
>
> ls -l | awk '{print $1}' | grep s
> it just prints the permissions having s bit.
>
>
> --
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--
=======================================================
Alexander Spanke System Analyst
NEC High Performance Computing Europe GmbH
Prinzenallee 11 D-40549 Duesseldorf, Germany
Tel: +49 211 5369 146 aspanke@xxxxxxxxxxxx
Fax: +49 211 5369 199 http://www.hpce.nec.com
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