matt, you want to create a wrapper script, OR have the export of your http_proxy var on your crontab line seperated from your command by an ; or && ; means that it'll run the following command whether or not the first one succeeded && means that it'll only run it if the previous command completed successfully if this is for apt (apt-get / apt-cache), then you can modify the apt.conf file (do a search for the word proxy) and you can set it up in there and be set. now, you could also create a wrapper script create /usr/local/bin/my_wrapper (or whatever you want to call it) here are the contents -cut -------------- #!/bin/bash export http_proxy='http://www.myproxy.com:80/' the command -cut -------------- now, run this chmod +x /usr/local/bin/my_wrapper this makes the script executable. now add /usr/local/bin/my_wrapper to your crontab. -d Matthew Benjamin said: > Can someone tell me how to create a system variable. For instance I > would like to create a variable called http_proxy that will be available > for a cronjob. This requires the variable to be available to the process > when no one is logged in. Export does not work because it disappears > when you log off. editing the /etc/profile file to include this does not > work because the variable is created as an environment variable and only > exits while you're logged on. That's my dilemma. Please help. > > mattB. -+(duncan brown -+(duncanbrown@xxxxxxxxxxxxxxxxx -+(http://www.linuxadvocate.net Blessed is the man who, having nothing to say, abstains from giving wordy evidence of the fact. -- George Eliot
