> On Fri, Nov 23, 2007 at 5:48 PM, "Dmitry Adamushko"
<[email protected]> wrote:
> The only legitimate possibility of having the fair_sched_class
> returning no task in this case is when 'rq->nr_running ==
> rq->cfs.nr_running == 0'.
Yes, I think so.
> iow, a possible optimization would be just the following check :
>
> if (rq->nr_running == 0)
> return idle_sched_class.pick_next_task(rq);
> at the beginning of pick_next_task().
>
> (or maybe put it at the beginning of the
> if (likely(rq->nr_running == rq->cfs.nr_running)) {} block as we
> already have 'likely()' there).
>
But that might add a test before the case we want to optimize the most.
I just thought of taking advantage of a case where we know
rq->nr_running==0, instead of throwing away that information.
Thanks
Nikanth
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