Tomasz Kłoczko <[email protected]> writes:
> Some data showed by top command looks like completly trashed.
> Fragment from top output:
>
> Mem: 2075784k total, 2053352k used, 22432k free, 19260k buffers
> Swap: 2096472k total, 136k used, 2096336k free, 1335080k cached
>
> PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ SWAP nFLT WCHAN COMMAND
> 14515 mysql 20 0 1837m 563m 4132 S 39 27.8 27:14.20 1.2g 18 - mysqld
>
> How it is possible that swap ussage is 136k and swapped out portion of (in
> this case) mysqld process is 1.2g ?
SWAP is just VIRT - RES. It means that 1.2g of the allocated virtual
address space is not resident, but it does not mean that all of it is
written to the swap space, it can also be part of a file based mapping.
Andreas.
--
Andreas Schwab, SuSE Labs, [email protected]
SuSE Linux Products GmbH, Maxfeldstraße 5, 90409 Nürnberg, Germany
PGP key fingerprint = 58CA 54C7 6D53 942B 1756 01D3 44D5 214B 8276 4ED5
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