On 11/1/07, Jeff Garzik <[email protected]> wrote:
> + lo = tf->lbam;
> + hi = tf->lbam;
> + ibyte = (hi << 8) | lo;
> +
> + lo = result_tf->lbam;
> + hi = result_tf->lbam;
That doesn't look right.
I suspect this was intended:
lo = tf->lbam;
hi = tf->lbah;
Torsten
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