Huang, Ying wrote:
The hibernation procedure with the patch set is as follow:
1. Boot a kernel A
2. Work under kernel A
3. Kexec another kernel B (crash dump enabled) in kernel A.
4. Save the memory image of kernel A through crash dump (such as "cp
/proc/vmcore ~"). Save the "jump back entry".
Doesn't this also save the memory of kernel B?
5. Shutdown or reboot
The restore process with the patch set is as follow:
1. Boot a kernel C (crash dump enabled), the memory area used by
kernel C must be a subset of memory area used by kernel B.
Why is a third kernel needed? Why can't kernel B be used for this as
well? In fact, if kernel A has been compiled to be relocatable and
crash dump enabled, why wouldn't it suffice for all 3 instances?
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