On 9/20/07, Paul E. McKenney <[email protected]> wrote:
> On Thu, Sep 20, 2007 at 01:31:35PM -0400, Dmitry Torokhov wrote:
> >
> > OK, then what is the purpose of synchronize_sched() in -rt?
>
> To wait for all preempt-disable, irq-disable, hard-irq, and SMI/NMI code
> sequences to complete.
OK, so what spin_lock_irq[save]? Does is disable IRQs in -rt or not anymore?
If IRQs are disabled it appears that I can continue using synchronize_sched().
>
> > You really need to provide users with a replacement. There are several
> > drivers that use it and for example r8169 is not what you'd call a
> > 'low performer'.
>
> I did look at making a synchronize_all_irq() some time back, and all
> the approaches I came up with at the time were busted.
>
> But I just took another look, and I think I see a way to handle it.
> Either that, or I simply forgot the way in which this approach is
> broken...
>
> I will stare at is some more.
>
Thank you.
> > I guess I can switch i8042 to use synchronize_irq(). That still works
> > in -rt, doesn't it? That still leaves atkbd...
>
> Yep, looks that way to me. The only difference that I can see is that
> in -rt, concurrent synchronize_irq() calls on the same descriptor mean
> that the guy that gets there second has to wait for the next interrupt
> to happen.
>
Does this mean that there is a possibility for a thread to hang in
synchronize_irq() if that second IRQ never comes?
--
Dmitry
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