Hi,
On Mon, 10 Sep 2007, Jan Beulich wrote:
> --- linux-2.6.23-rc5/scripts/kconfig/menu.c 2007-09-07 16:48:23.000000000 +0200
> +++ 2.6.23-rc5-tristate-choices/scripts/kconfig/menu.c 2007-09-03 10:29:41.000000000 +0200
> @@ -235,16 +235,23 @@ void menu_finalize(struct menu *parent)
> sym = parent->sym;
> if (parent->list) {
> if (sym && sym_is_choice(sym)) {
> - /* find the first choice value and find out choice type */
> + /* find out choice type */
> + enum symbol_type type = S_UNKNOWN;
> +
> for (menu = parent->list; menu; menu = menu->next) {
> - if (menu->sym) {
> - current_entry = parent;
> - menu_set_type(menu->sym->type);
> - current_entry = menu;
> - menu_set_type(sym->type);
> - break;
> + if (menu->sym && menu->sym->type != S_UNKNOWN) {
> + if (type == S_UNKNOWN)
> + type = menu->sym->type;
> + if (type != S_BOOLEAN)
> + break;
> + if (menu->sym->type == S_TRISTATE) {
> + type = S_TRISTATE;
> + break;
> + }
> }
> }
> + current_entry = parent;
> + menu_set_type(type);
> parentdep = expr_alloc_symbol(sym);
> } else if (parent->prompt)
> parentdep = parent->prompt->visible.expr;
If I understand it correctly this makes possible to override the type of
choice symbol, so this loop should only be done if the type is not
S_UNKNOWN.
> @@ -253,7 +260,16 @@ void menu_finalize(struct menu *parent)
>
> for (menu = parent->list; menu; menu = menu->next) {
> basedep = expr_transform(menu->dep);
> - basedep = expr_alloc_and(expr_copy(parentdep), basedep);
> + dep = parentdep;
> + if (sym && sym_is_choice(sym) && menu->sym) {
> + enum symbol_type type = menu->sym->type;
> +
> + if (type == S_UNKNOWN)
> + type = sym->type;
> + if (type != S_TRISTATE)
> + dep = expr_alloc_comp(E_EQUAL, sym, &symbol_yes);
> + }
> + basedep = expr_alloc_and(expr_copy(dep), basedep);
> basedep = expr_eliminate_dups(basedep);
> menu->dep = basedep;
> if (menu->sym)
Hmm, if you want to do it this way, I'd prefer you add a parentdep_bool
and simply do:
dep = (menu->sym && menu->sym->type != S_TRISTATE) ?
parentdep_bool : parentdep;
Otherwise it looks ok.
bye, Roman
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