On Wednesday 25 July 2007 10:05, John Sigler wrote:
> # cat /proc/interrupts
> CPU0
> 0: 37 XT-PIC-XT timer
> 1: 2 XT-PIC-XT i8042
> 2: 0 XT-PIC-XT cascade
> 7: 0 XT-PIC-XT acpi
> 10: 175 XT-PIC-XT eth2, Dta1xx
> 11: 1129 XT-PIC-XT eth0
> 12: 4 XT-PIC-XT eth1
> 14: 21482 XT-PIC-XT ide0
> NMI: 0
> LOC: 161632
> ERR: 0
> MIS: 0
>
> IRQ 10 is shared between a NIC and an I/O board.
>
> For eth2, the kernel said:
> ACPI: PCI Interrupt 0000:00:0a.0[A] -> Link [LNKC]
> -> GSI 10 (level, low) -> IRQ 10
>
> For Dta1xx, the kernel said:
> ACPI: PCI Interrupt 0000:02:0e.0[A] -> Link [LNKC]
> -> GSI 10 (level, low) -> IRQ 10
>
> Is it possible to avoid the two boards sharing IRQ 10?
Maybe. In this configuration, INTA of the two devices
is physically connected to the same wire on the device-side
of the interrupt re-mapper -- so you'd have to change the configuration.
If you have an IOAPIC and can enable it, that will not hurt --
though unless something else changes, these devices are still
tied together on the device-side of the mapper.
So if you can physically move one of the devices to another slot
that is your best bet.
I'd need a bunch of info from your system to tell you what
you can do ahead of time, including full dmesg, lspci -vv
and acpidump.
-Len
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