[]
> > > sed -i -e 's/^\t* \(\w*:\)/ \1/' "$@"
> > >
> > > which will replace the leading tabs and spaces with one space.
> > > It should leave case labels unmolested, as they should be indented with
> > > tabs, not 6 spaces.
> > >
> > > Any regexp ninjas want to have a go at something better?
> >
> > I'm the one. Trying to write portable, optimized and easy to
> > understand scripts [0].
> >
> > Please, describe more what must be done, and i will do it. Case labels
> > are handled very strangely in you example.
>
> OK. indent will indent labels to a column number that's a multiple of
> 8, plus 6. So it may start in column 6, 14, 20, 28, etc. I'm not quite
> sure what the definition of a label is; I had it as \w*: up there, but I
> don't know if that would match the _. The point is to *not* handle case
> labels, only goto labels.
t=`printf '\t'`
sed -i "s_^\($t*\) *\([^:]*:\)_\1\2_" "$@"
^-_
I'm not sure about leaving one space `here, otherwise it removes
spaces between (supposedly right indented) line start, i.e. nothing or
tab(s), and a label, i.e. `label_name:' without space before colon;
`label_name' here actually not a colon, let's leave that kind of
breakage to compiler.
The variable $t is used for readability of the regex and because POSIX
BREs leave undefined characters after a backslash, POSIX sed defines
only \n as a new line.
--
-o--=O`C
#oo'L O
<___=E M
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