On Mon, Jun 18, 2007 at 10:07:21AM -0700, Jeremy Fitzhardinge wrote:
> Denis Cheng wrote:
> > From: Denis Cheng <[email protected]>
> >
> > the explicit memset call could be optimized out by data initialization,
> > thus all the fill working can be done by the compiler implicitly.
>
> How does the generated code change? Does gcc do something stupid like
> statically allocate a prototype structure full of zeros, and then memcpy
> it in? Or does it generate a series of explicit assignments for each
> member? Or does it generate a memset anyway?
>
> Seems to me that this gives gcc the opportunity to be more stupid, and
> the only right answer is what we're doing anyway.
I checked with gcc 4.2, and gcc is quite clever:
If an array is big, gcc uses memset.
If an array is small, gcc does it directly in assembler.
> J
cu
Adrian
--
"Is there not promise of rain?" Ling Tan asked suddenly out
of the darkness. There had been need of rain for many days.
"Only a promise," Lao Er said.
Pearl S. Buck - Dragon Seed
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