Re: [PATCH] MM : alloc_large_system_hash() can free some memory for non power-of-two bucketsize

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On Fri, 18 May 2007, Eric Dumazet wrote:

>  			table = (void*) __get_free_pages(GFP_ATOMIC, order);

ATOMIC? Is there some reason why we need atomic here?

> +			/*
> +			 * If bucketsize is not a power-of-two, we may free
> +			 * some pages at the end of hash table.
> +			 */
> +			if (table) {
> +				unsigned long alloc_end = (unsigned long)table +
> +						(PAGE_SIZE << order);
> +				unsigned long used = (unsigned long)table +
> +						PAGE_ALIGN(size);
> +				while (used < alloc_end) {
> +					free_page(used);

Isnt this going to interfere with the kernel_map_pages debug stuff?

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