Fix roundup_pow_of_two(1)
1 is a power of two, therefore roundup_pow_of_two(1) should return 1. It does
in case the argument is a variable but in case it's a constant it behaves
wrong and returns 0. Probably nobody ever did it so this was never noticed.
Signed-off-by: Rolf Eike Beer <[email protected]>
---
commit 01ceeffac83011f0b5021013cc4abd1c4f291df5
tree 7da59df51617d7cebd55e4361019181645a17e10
parent ab35916f807eb4f2019a208e96cb0bddbb91dfc3
author Rolf Eike Beer <[email protected]> Thu, 17 May 2007 23:43:54 +0200
committer Rolf Eike Beer <[email protected]> Thu, 17 May 2007 23:43:54 +0200
include/linux/log2.h | 2 +-
1 files changed, 1 insertions(+), 1 deletions(-)
diff --git a/include/linux/log2.h b/include/linux/log2.h
index 57e641e..1b8a2c1 100644
--- a/include/linux/log2.h
+++ b/include/linux/log2.h
@@ -159,7 +159,7 @@ unsigned long __roundup_pow_of_two(unsigned long n)
#define roundup_pow_of_two(n) \
( \
__builtin_constant_p(n) ? ( \
- (n == 1) ? 0 : \
+ (n == 1) ? 1 : \
(1UL << (ilog2((n) - 1) + 1)) \
) : \
__roundup_pow_of_two(n) \
-
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